You can solve this, right Yea Forums?

you can solve this, right Yea Forums?

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I know you could do like a probability tree or whatever they're called but for 52 cards that might take a while, and I don't know any shorthand formulas for it

UHHHHHH
ZERO

t. retards

1,000 right?

correct

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500 times

There's 20 bowers and 20 people they each need to bow to, so 400

60?

correct

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20

21 people you forgot the teacher

One

The teacher won't be bowing. Just receiving.

to elaborate, there are 20 students to start off with (the teacher does not bow, but we'll deal with that in a second).

each of the 20 students must bow to the other 19, so that's a total of 380 bows. they must also then bow to the teacher.

in other words, each of the 20 students must make 20 bows (to the 19 other students and the teacher)

but what if they only have to bow to everyone all together once, so each person only bows one time? also what if it means you from the perspective of a person involved, in which case you would see no bows as you yourself would be bowing. shit puzzle.

If shuffled thoroughly, that means they are perfectly distributed or almost perfectly distributed.
So that means if you check the contents 1000 times without ever shuffling them again, you'll find that they have an equal number of red:black every single time.

it's a trick question, you're not reading it closely

>tfw we'll never get another classic Layton game like the ones on the DS
This hurts too much.

Aren't there like 6 3DS Laytons?

>mfw too stoopid for these threads

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low quality bait, no one is this stupid

user, you have two sets that mirror each other completely. 26 red cards and 26 black cards. No matter how you shuffle it, what isn't in one pile will be in the other, meaning that black and red quantities are always opposite, meaning that if there's one red in a otherwise wholly black pile, there must be a black card in the other one.

the number of red in one pile of a deck split in half will always equal the number of black in the other pile

you guys gonna solve this?

Trying, it's tough.

41286 - 7953

I'm very slowly working my way through the series, and I'm on the fifth game right now (first on the 3DS). The puzzles really dropped in quality after the original trilogy of games, so it's a slog to get through. On a side note, Lucy Baker from the mobile Layton Brothers game is cute!

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GOT IT
> 4 1 2 6 8
> - 7 9 3 5

these are the two solutions, great job

this one is a short one

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Yea, but the 3DS ones changed the art style and tried to implement the 3d gimmick in an awful way. The original trilogy was charming and had some great artwork. Also the puzzle quality, like said.

God, Layton had the least graceful leap to 3D in recent memory. Those models were godawful. You can tell they still had the art direction, but everyone looked absolutely atrocious. A far cry from the straining of the original DS's graphical limitations the original trilogy had.

Given a recent court order, zero.

1/8

1/4?

One eighth

yeah honestly it really turned me off of them, especially the fact that you don't use the fucking touch screen to tap on the goddamn environments anymore.

yep

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10 x 10 = 100
1 x 20 = 20
120?

1/5th

True. Layton has an amazing artstyle and it had nothing to gain going 3d. You could definitely feel the artists having trouble trying to implement things in 3d

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these games have tons of puzzles like this but i don't feel like solving this one since I just finished The Lost Specter like 3 days ago and there's at least 3 of these in there

no, i dont even know my multiplication table

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correct

this one is kind of fun if you've just done the rest and quickly realize what large blocks are eliminated


this is another trick one, although in my opinion noticing the trick is very useful for dealing with certain math problems in life which behave similarly

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Katrielle is cute, but is her game complete shit? I kinda wanna get the Switch version when that comes out.

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59 minutes

59 minutes?

59 minutes

yep

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puzzles are high quality as i remember

20?

nope

26

I've always wanted to play these games but I can't be bothered with an emulator. Is it android as well?

5+5 for the total height
5+5+3+3 for total width
26 total

23

yes

might quit for a while to go play some of spectre, if you guys wanna keep this going till I come back
layton.neoseeker.com/wiki/Main_Page

they just started re-releasing them, I think the first two are out. honestly just emulate them, they have no 3d

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Uhhhh 32.5?

You can use Drastic, but desu some Puzzles are hard to solve if you don't own a Note or a phone with a Stylus. Some of them are a bitch and a half to input

150

1/7
Move the diamond shape to mirror itself four times, one for each side. That covers a lot of the flag and gives you 5 diamonds, and leaves 4 small triangles, enough space to make 2 more diamonds. So 1 diamond is 1/7 the total space.

correct

Except the diamond is 1/8. You can turn the diamond into two rectangles each 30x20 inches, which in total have an area of 1200 sq. in. You can calculate the area of the entire flag itself and figure out the answer from there.

these games are for 9 year olds and most adults have trouble thinking about fractions like 1/7 desu

The diamond is in the exact center of the flag. If you were to put it in a rectangle with the same alignment as the flag, that rectangle would be one quarter the size of the flag.
The diamond would have one half the total area of that rectangle.

Flag is 9600 or 8:12
If you think of center area as a rectangle it is 2400. The diamond is exactly half of that rectangle(imagine putting a cross through it, you get four rectangles split diagonally in half) making it 1200, or 1/8 of 9600

>The original trilogy was charming and had some great artwork.
but there was 4 games on the ds.

440?

test