Giant mechanical spider

Maybe balance a little to the left but generally balance since its only the water

No you dumb fuck, it will tip to the right. What a waste of trips

if it's sensitive enough to register the weight of the ping pong ball + the string, it will tip to the left. The steel ball has volume but effectively no weight.

If it's less dense than water it will float on the surface and then you have the weight of the string to consider.

forgot to explain:

on the left- the ping pong ball is not pulling itself or the cup up, it is being pushed up by the water (buoyancy). All you've done is add the weight of a ping pong ball.

Right side: Its just a steel ball being dipped in water. The weight is still on the string and supporting beam. It is only displacing water.

Hell, after explaining it I'm changing my answer to tips down on the left side since its equal amounts of water on both sides, plus the weight of a ping pong ball on the left.

Imagine being so stupid as to think the ping pong ball will do anything. The ping pong ball is INSIDE the system. that means it cannot change anything. Obviously it will stay ballanced

Fuck you retard. Trips of truth. I'm right

It would shift to the left at first, then a bit of water would leave the left beaker and it would end up shifting to the right

I think we assume that the ping pong ball and the string are weightless

Draw the free-body diagram. If the ball has volume it displaces water, if it displaces water there's a buoyancy force, and if there's a buoyancy force there's an equal and opposite reaction force.