Can someone do this exercise for me...

Can someone do this exercise for me? I'm in the middle of an exam and I'm going to go wrong if I don't do this please help me

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>do my 8th grade math work for me!
fucking lazy spics

x=-3

76/6

Lel

Can you send me a picture of the procedure? If I put only the result, they will not be able to evaluate me, sorry for the inconvenience

Wtf is that ? I'm studying college maths and I never seen this [ ] matrix before

my guess is determinant = 0

you don't put the matrix like that?

when I was in college algebra we just put the matrix in our calculator, I wasn't taught any other way

Solve this for X:

-2(3*2-2*(-1)) +x(0*2-2*4) + 5(0*(-1)-3*4) = 0

Thanks user

help me with another?

[(-2*3*2)+(-x*2*4)+(5*0*-1)]-[(5*3*4)+(2*1*-2)+(2*-x*0)]=0
(-12-8x-0)-(60-4-0)=0
-8x=-44
X=44/8
X=10.5

Just try and min max your points at this point. Study harder and more efficiently for the next test. I can only imagine it's almost over and you're wasting tons of time looking at Yea Forums

Here is the procedure
I checked the answer with a calculator , assuming you were looking for the determinant

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Oops my bad , actually remove the minus the correct answer is x= 76/8 (simplifies 19/2)

Thank you all, this teacher did not send these exercises in class and I am confused

If x = -9.5, the second column is a linear combination of -1 of the first column and 3/2 of the third column, hence the matrix is singular (determinant is 0).

Can you help me with this one?

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This one was long , too lazy to do it by hand lol

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Which year are you in OP?

finishing high school, this year I entered user university

Thanks to all who helped me, I already gave the proof, I will give you news of the note on Wednesday