Just thought of something... if a very fat man goes to prison, do they have to search inside his flaps...

19

48
pleb tier

Attached: Chap-pipe-man.jpg (1293x1485, 993K)

60

22.5

23

19.

shoes = 10
man = 5
cone = 4

This. It's 60 you fags.

10 + 5 =15

15 * 4 = 60

40,5

43

It's 5 x 4 not 5 + 4
It's 30

5+5x2=30?

Attached: 1367151521963.png (401x325, 202K)

You do 5 x 4 first then you add 10
Fag

12

No you don't. The sequence is obvious. If it had been written differently then you'd be right. But's it's not and you're not.

10 + 10 +10 =30
5 + 5 + 10 = 20
4 + 4 + 5 = 13
5 + 19 * 2 = 43

26?????

PEMDAS you stupid fuck.
Therfore, it's
5+(4+5+10)*2=
5+19*2=
5+38=
43

too late boyo

The math problem is actually flawed. You have to assume a numerical value for the perceived half of one image but it doesn't necessarily directly correlate to being half. In truth the 'half' images could represent 90% of the numerical value.

this.

Attached: 1565734181010.jpg (1024x636, 78K)

the man is holding two cones

mel is the best

28

10+10+10=30
5+5+10=20
4+4+5=13
5+(19x2)=43

It doesn't matter you fuck, you always multiply before adding. Basic rules of math

It's 23 you mongoloids
5 + ((5+4)x2)
5 + (9x2)
5+18
23

Attached: vSWqcrNL.jpg (680x680, 43K)

It's 23.
5+(9×2).
One shoe (5) + (one strange looking guy (5) with two russian (4) wraps x one single russian wrap (2))

its 43 retards

I was waiting on this. Fucking kike is carrying two cones so he's a 9 and not a 5. Sneaky jew.

Nevermind it's 43

60 without Bedmas
30 with Bedmas

he has shoes on

6x = 30 (x = 5)
2y + 2x = 20 (y = 5)
4z + y = 13 (z = 8)
x + y + z = n (n = 18)

A lot more then I assumed.

48

Attached: 20190907_140213.jpg (1080x1062, 739K)

...and the guy wears a pair of shoes.

You are implying parenthesis that don't exist.
>meme arrows

88

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do you even know how maths work

a+a+a=30
b+b+a=20
c+c+b=13
a+b*c=x

Nothing else then 10 times 3 is equal to 30 when it's the same number added three times in a row

a=10
b+b+10=20

So b got to be 5

5+5+10=20
c+c+5=13

13-5=8
So c got to be 4

4+4+5=13
a+b*c=x
10+5*4=x
10+20=x
x=30

2x + 2x + 2x = 30
y + y + 2x = 20
2z + 2z + y = 13

shoe = 5
boy = 5
newspaper = 4

(3x + y + 2z)z
[3(5) + 5 + 2(4)]4
15 + 5 + 8 x 4
28 x 4
112

(3x + y + 2z)z
[3(5) + 5 + 2(4)]4
15 + 5 + 8 x 4
28 x 4
112

15 + 5 + 8 x 4
15 + 5 + 32
52

Attached: 20190907_140756.jpg (1080x1694, 491K)

its 30 u degenerated fucks

Attached: 1024px-Who_you_callin_Pinhead_by_cusackanne-1-.png (1024x651, 713K)

Ups, only one shoe, that's a a/2=10/2=5
Therefore
a/2+b*c=x
5+5*4=x
5+20=x
x=25

What does it mean that the kid is holding two new papers? That's not like he gets mathematically mixed in new paper and become the postman..

Not "new paper" but "news paper" also there's dead flowers in them or something

I refer to the three terms in each of the four equations as slots. Assuming that items appearing in the same slot are summed, then:

s = shoe
b = boy
n = newspaper

2s + 2s + 2s = 6s = 30
s = 5

b + b + 2s = 20
2b = 10
b = 5

2n + 2n + b = 13
4n = 8
n = 2

Solving for ?:
b + (b + 2n + 2s) * n = ?
5 + 19 * 2 = ?
5 + 38 = ?
43 = ?
QED

10+5×4
If you used boomer math you got 60
If you used pemdas you got 19
If you fucked up on line 3 you got 30
If you mixed up the man and the cone you got 70

S = 10
P = 5
C = 4

S+S+S = 30
P+P+S = 20
C+C+P = 13
S*(P*2+C*2) * 4 = 10+8 = 18 + 10 = 28 * 4 = 112

What about those who got 25 because the kid holding the paper stuff don't seems to make sense by math?

Oh the figure even have smaller red shoes on.. What to subtract when the other shoes are now gone?

He has 3 cones

(4*10)*5 or 4*5*10 or 4*5+4*10? I don't think the cartoon can be used for math

When i was in jail their was a tremendously fat guy in the same dorm.
Do not know anything about flap searching. But he would only shower when their was no one else in their. i guess being in jail sucked enough and he did not wanna get made fun of like crazy for his gigantic ass.

x + (2x + 3z + y) * z

All of you are -10 iq brainlets
the answer is 19

14

its 43 dumbfuck

49

answer is 19 prove me wrong
(you can't)

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Hi9

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No

Well done OP, you trolled Yea Forums with a cartoon that can't present math, since the objects can't be logically reasoned with, mostly the person having shoes on and carring paper

Thier is only 1 shoe not a pair so it = 5 not ten the answer is still 14.

28

5+19x2
5+38
43

...

23 or 1255

PROBLEM 1
2x+2x+2x=30
6x=30

SOLUTION 1 ----- x = 5

problem 2
y + y + 2x = 20
2y + 2(5) = 20
2y + 10 = 20
2y = 10

SOLUTION 2 ----- y = 5

PROBLEM 3
2z + 2z + y = 13
4z + 5 = 13
4z = 8

SOLUTION 3: Z = 2

FINAL PROBLEM
x + (2x * y * 3z) * z
5 + (2(5) * 5 * 3(2)) * 2
5 + (10 * 5 * 6) * 2
5 + (300) * 2
5 + 600

FINAL SOLUTION 605

4x5=20
5+20=25

30

nvm I didn't see the shoes
43 or 130

Moron

Oh shit i did not the the multiplication symbole lol i am a dummy.
Answer is 40 then.

alternatively if you see him as holding 2 cones
x + (2x * y * 2z) * z
5 + (2(5) * 5 * 2(2)) * 2
5 + (10 * 5 * 4) * 2
5 + (200) * 2
5 + 400

FINAL SOLUTION 405

Man has 2 cones in his arms on the last line.....

20

Winrar

...

...

32?

43

And shoes

64, i didn't see the X

Winrar

it's also up for interpretation in the final question, where the second variable in the equation has ambiguous function.

Are you supposed to add? Or Multiply? It's not clear. Mathmatically, numbers grouped like that are multiplied, but some people might see it as "adding" to the picture

Underrated comment

The awnsers always 1488.

smh it's late 172 didn't see the two shoes and

32

86 fucking hell i've changed answers 4 times !

1. A single shoe has no definable number in this example (a pair of shoes could be worth $100, but a single shoe is worthless) so the formula is unsolvable.
2. Yes of course you idiot. They check your asscrack too.

never mind it's 48

>1. A single shoe has no definable number in this example (a pair of shoes could be worth $100, but a single shoe is worthless) so the formula is unsolvable.
You can't figure this out.
>2. Yes of course you idiot. They check your asscrack too.
You're a fat phuque who has been to prison.

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Have a friend who worked at a prison and yes they do, someone actually had a knife tucked between the flaps.

Omg. It's 25, but only if half a pair of shoes represents half the value of a full pair. you guys are so dumb

ITT: A bunch of smart people pretending to be retarded and a bunch of retarded people pretending to be smart

Attached: 1566369850286.jpg (640x481, 50K)

winnar.
anyone who says otherwise is a troll or a fucking mongoloid

Omg, nevermind

If we assume boy holding cones is the same value as boy without cones + the value of the cones he's holding and single cone = half the value of double cones and single shoe = half the value of pair of shoes, then its 23. Otherwise we don't know

TEACHER, PLEASE CHECK MY ANSWER

If you didnt get 43 as an answer, you are a brainlet. Since you retards need a step-by-step tutorial for simple math, here you go.

(Assuming half of an object is equal to half of its numerical value)

Shoes = 10
Man = 5
Cones = 4

The first lines are for the sole purpose to find the value of each object. (Shown above)

The last line consists of a (singular) shoe which would theoretically be equal to 5, a man holding two cones ( 4 ) with a pair of shoes on, and a singular cone (2)

(PEMDAS applies here)
The man x the cone (19•2)= 38
You would then add the shoe (5) for a grand total of:
43

Could be a Mongoliod Troll.

Attached: trolledb.jpg (480x350, 40K)

TEACHER, please check my FREAKING ANSWER!!!!!
I NEED YOUR ATTENTION AND YOUR LOVE AND APPROVAL (CRYING)
MOMMY AD DADDY DON'T LOVE ME ENOUGH
I NEED YOU TEACHER
I NEED YOU TO TELL ME THAT I'M EXCELLENT AND NOT LIKE OTHER STUDENTS
I NEED IT
PLEASE CHECK MY ANSWER -NOW-

21