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physics.stackexchange.com/questions/130688/which-way-does-the-scale-tip
discord
en.m.wikipedia.org/wiki/Argumentum_ad_baculum
twitter.com/SFWRedditGifs

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nothing or nothing

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Depending on the masses of the two different balls

you are a fucking idiot

Right

Short answer: It tips right
Long answer: physics.stackexchange.com/questions/130688/which-way-does-the-scale-tip

It will tip left.

-Both balls are the same size, so the weight of water in each cup is equal.

- Left side includes the weight of the ball, right side does not (since it's suspended from a string)

- A red herring is a fact that the ping pong ball is trying to float up and pull the string up -- the only reason it can float is because it is pushing the water around it DOWN. Therefore its weight is still included in the total weight of the cup.

the balls are the same size, so steel is heavier

Ping-pong ball will never be able to be held by string in water. It would simply fall to bottom. Making the question dumb

same size means same weight.

>being this dumb

>Ping-pong ball will never be able to be held by string in water. It would simply fall to bottom.

are you pretending to be retarded on purpose?

no it doesn't, size only takes into account the area, not the density of the object

the link above you stated otherwise

I'm the one who posted it btw

Great answer, user.

Neither.

your dense

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Assuming the balls take up the same amount of space, there's the same amount of water in each glass, meaning they weigh the same, and are balanced.
However, the ping pong ball is attached to the glass, and has buoyancy. The steel ball is suspended and will not affect the balance at all.

>Will eventually tip right

Water pushes down on the ping pong ball equally as hard as the ball pushes up on the water. Buoyancy is irrelevant in this situation.

that answer says that since the ping pong ball is lighter than the water it will make it tip to the right. That is idiotic. Imagine 2 buckets of water on a scale, if you put 1000 tons of ping pong balls on one side, would that make that side rise?

Seems you're the dense one.

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Left. They have the same volume, so they displace the same amount of water, but the one on the left has a string in it, so it's slightly heavier.

noting will happen u stuped fuck!! noting!!!

It will tip to the right if the force due to gravity of the ping pong ball is less then the buoyancy force on the steel ball and vice-versa.

They have an equation and everything, and considering it's a physics boards(way more qualified than us) they have merit to their claims. And one of the answers given made sense to me

>Steel ball doing any buoyancy

so let's say i balance 2 swimming pools with 1 ton of water each, but in one side there were 500 lbs worth of ping pong balls tied to strings at the bottom of the pool. You are telling me that because ping pong balls float, the extra 500 pounds of plastic means nothing and would cause that side to rise??

This is correct.
You forgot to mention that the steel ball has no effect on the scale, since its weight is absorbed by the normal force of the framework.

Left will have net forces acting to pull it down greater than net forces acting on the right, as the top of the steel ball will transfer a portion of the forces from the water above it to the stand holding the ball. As it tips, more forces will accumulate on the steel ball as more water moves above it

Yeah this was obvious
>steel ball displaces water, but adds no mass as its mass is held by another object
>ping pong ball does have mass but the mass is so light that between its small weight and it being tied to the cup, the buoyancy of the air is stronger than the weight of the ball and creates a small upward torque

Precisely the opposite. The buoyancy force will act as you expect, you just misread what I said.

>Buoyancy is irrelevant in this situation
That's simply not true. If the ball was neutrally buoyant, as it seems like you're suggesting, then the string wouldn't be taught and you'd be correct. But ping pong balls float and are positively buoyant.
The ball pulls on the string because it's trying to reach the surface, making it taught. The string is attached to the glass. Very very slowly, the scale will eventually tip right.

The ping pong ball is pushed up by being displaced by the water being pulled down, which forces the ping pong ball up

Let's work through it.

Jars = same weight
Water = same amount obviously
Strings = weightless obviously
Ping pong ball = practically weightless I guess

The left jar has a flotation force pushing the ball up, therefore the ball is pushing the jar down, but via the wire it pulls up equally, so that cancels.

The right jar has a flotation force pushing the ball up, therefore the ball is pushing the jar down.

And down it shall go.

what a fucking retard

What "flotation force" exists in the right jar?

And how is the ball in the left jar pushing the jar down?

>Inb4 steel doesn't float

Checkmate nig-nogs

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Assuming as we're led to believe that the balls are equal in volume, the ping pong ball side will fall. weight of ball+string, while minimal, are acting on the scale. The steel ball does not act on the scale.

The ball displaces water, therefore it has an upwad flotation force equal to the weight of that much water.

This is why submarines don't fall to the ocean floor.

The left and right balls both have this flotation force pushing them up.
Every action has an equal reaction. They are both pushing their jar down.

No, look all you need to understand is net forces, and the right jar has less net forces pushing it down as the steel ball acts as a platform for the water above it, meaning that it has less net force applied to the jar on the right in a downwards direction. Ie 10% of the downward forces are applied to the steel ball and not the jar

Right, fuckwad.

They are acting on the scale yes, but they're acting negatively.
If they were more dense than water, and therefore at the bottom of the glass, then they would be acting positively on the scale and you'd be right.
But they are not.

>a platform for the water above it

Water is a liquid. It's not stacks of coins.

Look, guys, don't mess with me. I'M AN ENGINEER. I can use a slide rule.

break a whole in that ship and see if it stays afloat

>USS Cole

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>a whole

Oh so ballast tanks have nothing to do with submarines not sinking.
Got it.
I'll just go turn in my warfare pin to my Captain then.

The ping pong ball is attached to the container which is acting on the scale. It doesn't matter where the ping pong ball is or how bouyant it is. It can't lift the container. That's not how physics works. You can't make something lighter by putting more stuff in it.

Based submariner, tell us some funny stories. I KNOW YOU HAVE SOME.

I never said that.

If I was wrong, point out my error, then present your own theory of floating.

capeshit
kill yourself

You can if that stuff is air.
Which is what a ping pong ball is mostly made of.

It's all about relative densities. If you make the object less dense than it's surrounding medium, it will rise.

It's not

Both balls are displacing the same amount of water, but in one cup the pingpong ball is also pushing back on the water while in the other it's suspended by a string.

Imagine cutting the string on the pingpong ball. It will float on top of the water and add to the total mass of the cup. Pulling it under doesn't change that.

However, lowering the steel ball into a cup of water only displaces the water, until the steel ball rests on the bottom.

I think we can ignore the weight of the ping pong ball (and the air within it).

The displaced water is many times heavier, and that's the differential between sides.

if we assume that both stell ball and pinpong ball are the same size
left
reason: steel ball is not part of the equation
both sides are missing part of the water that is given by the size of the spheres
that means left side contains as much water as the right side.
however left side also contains the pinpong ball aka weight of the plastic + weight of the air trapped inside of that ball
steel ball is not part of this equation, it simply removes water from the right side

> tldr; tips left, if you disagree you're a fucking stupid nigger and you should lose your voting right

I disagree because I'M AN ENGINEER and nobody seems to realise what that means.

It means I'm playing this game in God Mode.

>The ball displaces water, therefore it has an upwad flotation force equal to the weight of that much water.

Yes, but it is not enough to overcome the ball

>This is why submarines don't fall to the ocean floor.

Nope

>The left and right balls both have this flotation force pushing them up.

The force is the same yes, but it has more effect on the left ball because of weight/density

>Every action has an equal reaction. They are both pushing their jar down.

True, but relatively speaking, the net forces on the left jar are negative, while right jar is neutral.
This is because the right jar is not coupled to the ball, so the left jar doesn't have to overcome any of the right balls forces, except for the minimal friction from the ball moving through the water when right jar moves down.

Left jar is negative (very slightly) because of the rising forces acting on the jar, through the string. If the ball was neutrally buoyant, or negatively buoyant, then it would be different.

The amount of water is exactly the same

It's the pingpong ball that makes the difference here, even tough it's small.

>no u

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weight is not a factor, only displacement

The amount displaced is assumed to be the same in both glasses.
You're ignoring the only difference between the glasses.

Left, both have the same amount of water in them but the left one also has the weight of the ping pong ball

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So, accordingly to these retards pic related weighs nothing?

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Displacement is the same.

Refer to

Engineer here.

The baloon weighs exactly as much as that amount of air. I never said it was nothing.

I could have two billion liters of water, which weighs 2000 tons

But still
2000tons+pingpongball>2000tons

That's not the only difference.

The other difference is what's the wire connected to.

discord
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discord
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But it's less than 2000 tons + the weight of a water sphere

If you're going to over exaggerate one value, you have to over exaggerate all of them proportionately.
Otherwise you just look stupid.

Very Epic

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You are claiming that right will rise, right?
So let's clear up some facts:
>steel ball is not part of the equation.
>it leaves left jar (water+ping pong ball) vs (only water).
>ping pong ball does weight.

Therefore:
>in L and R there's the same weight/amount/volume/mass of water.
>so L has the additional weight of ping pong ball.

You cannot rob me for owning a motorolla G4, rapping, and doing math on my calculator, and watching anime, or for fucking bitches. You cannot rob me of my women (Slight tug of war of women debates) you cannot rob me for fucking women though this is fact. Or men. Just because your son takes dick in his ass isn't my fault. I'm a very handsome gentleman.

Engineering right back into the thread to say

RIGHT WILL FUCKING GO DOWN

as I've been saying all along.

Also see:

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...

Its tethered to the seesaw though

This is wrong because:

Left: water etc + ping pong ball

Right : water etc + the weight of the missing sphere of water

en.m.wikipedia.org/wiki/Argumentum_ad_baculum

>ALRIGHT IM RIGHT AND YOU ARE NOT BECAUSE WHO I AM AND WHAT I REPRESENT AND WAHT I CLAIM TO KNOW, DESPITE I DONT PRESENT ANY ARGUMENT.

Learn some rhetorics first.

Indeed, right: water etc + (the weight of the missing sphere of water = 0)

That depends - do the balls displace an equal amount of liquid? (I assume blue is supposed to symbolise water)
There's a little more string in the ping pong side than the steel ball side - or has that been compensated for?
Data, data, data, can't build a wall without bricks.

Pic unrelated

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I already presented the complete argument. If you didn't understand it, it's because you didn't study mechanics because you're NOT AN ENGINEER.

Very good attempt at turning your stupidity into "oh I was just troooooolllinnnn"

Your argument is invalid.

Also, HURR DURR AMAN EENJINIER!!11!!

I'm exaggerating the ratio

I have some submariner stories, most involving dicks. But the thread is pretty full already

Besides, it doesn't fucking matter what values you use

X = random
R = random

X+R>X

Retard

Yeah, but in the picture, the water sphere is displaced in both cups.

Ow, and yes, X >= 0 and R > 0

Obviously

Balloon+basket

Otherwise it would be a big round parachute

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i thought this was possible when i was 3

See:

Yes, but on the left side the displacement force is transferred through the wire to the jar. It cancels.

and the dudes chilling in the basket

Ow shit, forgot about those

You don't get it.

The weight of the missing sphere is pushing the jar down.
Because flotation.

>Uhm,
>Seems about right. But that upward force is also put back on the cup by the increased water pressure.

Lets say I've got 1000ml of water in each cup:
So I've got 1000ml of water + a pingpong ball
And on the other side I've got 1000ml of water...

So I've got the mass of the water L and the mass of the pingpong ball P

Which one is bigger?
L+P or L

id ague that if the pingpong ball was not there it would tip left because distance from the gravitational centre is increased

OP here, I will explain it for you all since the thread is dead

The right hand system is the weight of the ball + the air inside
The left hand system is the bouyant force on the metal ball

so the question is, which is greater? Remember they are the same volume, meaning the bouyant force on the right is the same as that on the left. Since we know that the ping pong ball floats, we know that the weight of the ball is less than the bouyant force on the ball, so we know it will tip right

thanks for playing

Oops, switch left for right

Right, because my dick will get hard and push the left side up.

Steel ball side goes down until the ball is no longer submerged because the buoyant force is cancelled out by the ping pong ball tethered to the bottom.

Left you retards

This. We have to assume that the buoyancy force is greater than the mass of the ping-pong ball, which is reasonable as the ping-pong ball wouldn't float if it wasn't

>Left you retards
I hope you is trollin'