Get on his level

get on his level
>pro tip
you cant

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Nice bait nigger

15

>you can't

30÷3=10, piston=10
20-10=10 10÷2=5, tire=5
9-5=4 4÷2=2, 2x McPherson struts=2

>5+1×10= 50

(5+2)*10 because 5+(2*10) would be retarded.

agreed user

Multiplication comes first, dumbass, so it's 5 + 10 = 15

/thread

Your retarded 5+1=6 6×10=50, kys faggot

are you just gonna ignore the basic rules of math because it's retarded

3A = 30, A = 10

A + 2B = 20, 2B = 10, B = 5

B + 2C = 9, 2C = 4, C = 2

B + (C * A) = X

5 + (2 * 10) = X

5 + 20 = X

25 = X

this isn't even algebra 1, this is 4th grade math.

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Thats easy the answer is ?

there are 4 pistons in C and only one in the final question so it would be 5 + (1 * 10)

double shocker is 2 but is single shocker 1 or square root of 2 ?

well that's fucking retarded.

The pistons are the grey ones, i think youre referring to the struts (red ones)

25. I hope

Congrats! You just failed 4th grade math.

I think what user is attempting to say is the answer is questionable

Assuming that the doubled struts are equivalent to two times a single strut.

x=Piston
y=tyre
z=strut
a=question mark
> x+x+x=30
> x+y+y=20
> y+2z+2z=9
> y+z*x=a

Solving for x (piston):
3x=30
x=30/3
x=10

Substituting back into remaining formulae:
> 10+y+y=20
> y+2z+2z=9
> y+z*10=a

Solving for y (tyre)
10+2y=20
2y=20-10=10
y=10/2=5

Substituting back into remaining formulae:
> 5+2z+2z=9
> 5+z*10=a

Solving for z (tyre)
5+2z+2z=9
5+4z=9
4z=9-5=4
z=1

Substituting back into remaining formulae:
> 5+1*10=a

Solving for a
5+10=a
15=a

Eh typo'd z as (tyre), in the last bit, should be (strut) but w/e

the fucking doubled struts got me

70
10+10+10=30
10+5+5=20
5+2+2=9
So 5+2×10=70

The only correct answer. Hardly surprising that a bunch of fucking Yea Forums NEETs failed it, though.

I am laughing my ass of that people fall for this facebook clickbait shit and really solve it...

kindergarten math ...

25 retards

15
old pasta is old

>70
>10+10+10=30
>10+5+5=20
>5+2+2=9
>So 5+2×10=70

wrong!

Last symbol is single not double (=1 instead of 2) in last equation - multiplication before add/sub

5+(1*10) = 15

It has 3 possible answers depending on :
if you don't see that it's a multiplication symbol you get the incorrect answer of 17.
If you see the multiplication symbol but you don't follow the BODMAS rule (*brackets of division, multiplication, addition, subtraction") you get 70.
If you obey the BODMAS rule you get 25.
Genius level over 9000. Ascension attained.

Attached: thats-not-a-ov4ts9.jpg (600x391, 32K)

final suspension symbol is just single ...
2 car suspensions = 2
1 car suspensions = 1

5 + (1*10) = 15

>If you obey the BODMAS rule you get 25.
another blind mate that doesnt see that the suspension symbol changed in the final row...

Answerrposted too early: it's 1 piston so the correct (bodmas answer) is 15.
The correct non-bodmas answer is : 60.

All of you are retards, the answer is 16. The first row is equal to 10 each. Each wheel on the second row is worth 5. The pair of pistons on the 3rd row is worth 2. Therefore 5 plus 1(there is a single piston, not a pair) plus10= 16

Yeah just saw that. I've re-assessed my life choices and posted the correct answer in response. At least 'I'm not gay: is my only possible comeback in this case.

>5 + 1 + 10

m8 its 5+1 x 10

Thats 15

Only that last symbol is not a plus its a multiply so you need to look up bodmas to get the 2 possible answers.

>single piston plus10

Attached: operator.jpg (229x143, 6K)

You only got one of the 2 possible answers: You need to look upand learn bodmas to get the other possible answer.

Kek. This.

10 shit stick
5 for rubber tire shit
2 for 2 poker jiggers.

so one tire one poker and a thingy boxer is 10+1+5 so its something like that. Unless its complicated and gay. Then no matter what its not worth shit.

>x+x+x =30
>x=10
>x+y+y=20
>20-10=10
>y=5
>y+z+z=9
>9-5=4
>z=4
>y+a*x=?

>5+a*10=?

I don't know how to solve this.
But I'm fairly sure that a =/ 1 like these idiots keep thinking.

You're right - it all hinges on whether the doubled sprung struts indicate twice a single strut, or something else entirely.

Im gonna take a flying wild thats its a single cylinder gas power unicycle with a strut on it.
That is all you fucking get from me

yes but its not for fat people

25

You are either a poe or retarded. I can't decide

17 ?

see:

Oh shit n/m then I missed that

25

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These guys have the 3rd possible answer.
I'll add this to my 2 possible answers (bodmas answer and non-bodmas answer).
Thanks.

15

Simple observation and arithmatic.

Attached: b1f.gif (332x352, 1.47M)

Sixx

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see
or for an even more complex answer see:

If XY=X*Y then XX would be X*X so the strut would actually be worth sqrt(2)
So 5+1.414*10=19.14
Theres the real answer

you fucking idiots you have 50iq and 1cm dicks

there are no logs.

/thread

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>your retarded

You're not fooling anyone by threading your own shitty

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15

25. And please don't say "for geniuses only", when it's a basic math equation which every 10yo should be able to solve...

It's 70, every other poster is fucking retarded.

99.99% will fail

Attached: 1525256608316.png (826x1097, 227K)

15

see
or for an even more complex answer see:

Fuck. Got owned by the fact that there was only ONE strut, not two.

But then, I have to say that the answer is NOT 15, no more than it is 25.
I mean, where there are two variables near each other, WITHOUT a sign between then, we have to consider that an implied multiplication.

Which means that STRUTxSTRUT = 2. Which means that STRUT = sqrt(2).

So, the correct answer is 5 + 10sqrt(2).

70

It's a single piston you fucking idiot.

Single piston not double.

see
or for an even more complex answer see:

Single piston.

The answer is : niggers tongue my anus

You can't actually solve this, it has exactly 0 answers with the information provided. You can't assume that a double strut is the same as 2 single struts. With the information available it has to be dealt with as a completely separate variable which gives an infinite number of possibilities

Without showing the sum of 2 individuals equalling a doubling the single its basilly a trap leading to an erroneous conclusion .

This is correct.

Ayup, but that's not idiocy, merely the fact I got tricked by the OP's choice of symbols. Which is to say, good bait, 9/10 (for the sneakyness, AND for the multiple interpretations available for single and double strut symbols).

If you see that as separate symbols, then you are absolutely correct. If you see simply groups of two "strut" variables, then
is the correct answer.

As the OP is a troll, and it is intended to be imprecise, I'd say both these answers are correct, as long as we explain in our solutions the interpretation we used.

You can assume anything outside normal convention, as long as you make it clear that said assumption is being made. See > Assuming that...

The idiocy bit was
>please don't say "for geniuses only", when it's a basic math equation which every 10yo should be able to solve

Yes, and we both noticed that it is fucking 70, you fucking retards.

I mean this fucking retard for

thats not kurwa named pierdolony piston

bring those ids back i didnt reply to myself

Okay let's do this
a+a+a=30 so a=10
a+b+b=20 so b=5
b+cc+cc=9 so c=√2 OR -√2
so b+ca= 5+10√2 OR 5-10√2

Kek
I'm the one you responded to and I have no idea what you're talking about now but the answer is definitely not 70.

But it was not stupid, considering what I had seen (3 different variables only, with additions and multiplications).

So, considering that, it WAS a simple math problem every 10yo should be able to solve.

Of course, it's no longer true when you see that there is only one strut on the last line. But the conclusion was correct, it was the initial data (or data assessment) that was incorrect.

correct user

Oooooh, right, forgot the negative sqrt. Well played, user, I'm ashamed now.

Should we solve this in Complex space, instead of Real space ? :)

wtf is your problem ?

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>basic math equation which every 10yo should be able to solve
>not true when you see that there is only one strut on the last line
>still arguing
Idiot.

16

see
(You)
or for an even more complex answer see:

see
or for an even more complex answer see:

The reasoning was correct (and thus, not "idiotic"), only the data the reasoning was based upon was wrong.

If there was a problem, it was more of a sight problem than a brain problem, you jerk. And I'm pretty sure you fucking know it, too.

So I'm done arguing with you, troll, and I shall go full autist and flay thy hideous hide next time I encounter thee.

We should just call each other niggers and be done.

>you jerk
Kek.
I genuinely like your style and look forward to our next encounter.

It's been fun :)
See you, troll !

>Assuming that the doubled struts are equivalent to two times a single strut.
While this is the correct thing to do, who the fuck makes an assignment like this where you're supposed to assume that something that has not been defined should be visually deduced?

>3a = 30
>a + 2b = 20
>b + 2(2c) = 9
>b + c + a = x

a = 10
b = 5
c = 1

b + c + a = 16

Hope atleast one more person in this thread got the answer.

>who the fuck makes an assignment like this
Faggot op or some shitcunt of equal or lower value

This ofcourse assumes the double spring is equal to two single springs. If not then solution is different.

a+a+a=30
a=10
a+b+b=20
b=5
b+c+c=9
c=2
b+d*a=?
?=5+d*10

cant be solved

This thread just made my day.

wait nvm. thats a multiplication. No wonder I failed math.

Either 15 or 60, without parenthesis its impossible to know

Oops, I forgot pemdas, its 15

They all have different values to them the pistons are 10 each tires are 5 each shocks are 2 each
The question are just simple additon
The last question's multiplcation answer is 200

Did i understand this correctly?

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Fuck. Math was never my strong suit better luck time i guess

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Remember, multiplications before additions, so the answer is 25, and if you can't answer this, then you should be banned because you are not old enough to learn third grade math.

Attached: everyoneon4chanisstupiddotjaypeegee.png (842x960, 641K)

Again, as everyone already said in the thread, in the last row there's only one of those springs, so that 2 is actually a 1. The answer is 15