Well?

Well?

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Something like 1/16 pi?

how the fuck can it be 1/16 pi when the area of the whole small circle is 1/16 pi

The small circle is 1/8th,
but yeah, it might be 1/32 pi then. 1/4 of the small circle.

Reeeeeetaaaardè

the only right answer is
>I want to be a train when I grow up
bc No Child Left Behind

just use Riemann sums

wat

elegant solution.

Large circle r = 1/2
area = 1/4 pi
area of each wedge is 1/16
smaller circle r = 1/4
area = 1/16

We know that the smaller circle could be crammed into a wedge. All you need to find out then is the area of the three smaller parts of the wedge not filled, they will equal green. The one at 0,0 is the area of a square length .5 minus area of a circle radius 1/4 all of that over 4, which comes out to (1/4-1/16)/4 = .046875. The other two symmetric areas are i don't fucking know I'm pulling all of this out of my ass.

Without a height, or some assurance these are circles? Not enough information.

With said assurance?
this guy has it

0.0366

area of smaller circle is pi*r^2 = pi*0.25^2 = pi/16 = 0.196349541
area of overlap of the circles can be figured out with the formula for a symmetric lens as 0.159754226
difference is 0.036595315

Answer= (sector ABD - triangle ABD) - ( sector ABC - triangle ABC)
Where A and B are the two intersections, c is the center of the larger circle, and d is the center of the small circle.

1:45am don't feel like finding the numbers.

Easy calculus problem but I don’t want to do it

Test

A area small circle eqauals area small circle minus B area small circle

B area small circle eqauals 1/4 area small circle minus 3/4 area of small square minus are of small circle

Put the numbers in if this is your homework

working on it

almost got it

im not getting any pussy or money out of knowing this shit why the fuck should i care, the answer is post some loli sluts

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got it

thanks for inspiration

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here's my work

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Find intersection points (x1,y1) and (x2,y2), express circles in terms of x, integrate difference of functions from x1 to x2, express smaller circle in terms of y, integrate [function - x2] from y1 to y2, add results of two integrals. Two integrals are required as the smaller circle function is not one-to-one over the entire interval in either x or y.

No

Yes.

Show me how you find the intersection, cutie
You’ll get a nonlinear system of equations. It’s a bitch.

Is correct.

Again Is correct, you don't have enough to solve for the intersection the way you've described it.

The above correct way does work, but uses calculus. There is a way to solve it using only geometry, but I'm too lazy to reduce the cluster fuck of algebra I got it to

Can i see your algebra?

nerds

Literally takes time out of his day to let people know he isn’t like them