how smart is Yea Forums? can you solve these puzzles?
How smart is Yea Forums? can you solve these puzzles?
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On it
I dont get the first one on top. What is that?
One on top left: move the top of the 9 to the left to make sixty=60
2ez
Further down on the left. Move the bottom left stick from 6 to get 5 tally marks = 5
WoRk It OuT
Got one
nice
Make every single one of the equation have the sign ≠ and you're done
LOL winner
Already completed
Let this thread die now.
In limit equation, make it
Limit as x tends to 8 of x^2-8x over x = 1
That's pretty advanced math
I need answer for this NAO
interdasting
judging from the others being solvable that one must be
>Yea Forums
>smart
>mfw
Not sure if this is an acceptable answer, but if we can compare different systems...
The "big square" one near the top if you move the two top horizontal ones over you get 100 which is a "big square"
how is 100 the same as "big square"?
it's a big square number
woah
Could this be a comparison?
+ == -++
Got another.
CXXXI=IC
goes to
CX/XI=IO (110/11=10)
Are the rest of you even trying?
Another hero
I'm amazed this even has answers
For the sum, turn
sum from T=1 to 7 of T/(5-T)=1
to
sum from T=1 to 7 of T/(5-1)=7
only 1 left now
I see more than 1 without solving
What are you talking about there's like 5 left
nice
s is correctt not this:
Made a summary of what we have. Tell me if I forgot something
Not your personal army faggot
good work user
how has nobody said cos0 = 1 yet?
A HERO!
great find
Are we stuck anons?
uh i have one thats kind of a stretch
bottom left. in the alphabet J is the 10th letter
J = 0 + 4(P)
J = 10 + 4(0)
10 = 10
so taking the stick from the bottom of the P and putting it in front of the 0.
But you can only move one, user. You cannot put a 1 before the 0
[1-2][5/2]=4 ---> [1 2][5;2]=9 ([5;2] means a 5 with a 2 bellow so a 2x1 matrice)
I'm moving the bottom of the P.
What im trying to say is that you cannot make a 1 with just 1 stick. you need two sticks.
BOOOOM!!!! MINDBLOW!!!
then the tally mark one is equally incorrect, as it is shorter than the other marks.
also [4-1][4-2]'=18-->[4+1][4-2]'=10
you skipped the ^7 exponent i think
I agree that the tally mark would be incorrect based on that assumption alone, but there is a detail on that one: the left side sticks are twice as big as the sticks on the right side.
that's fair. thanks.
it's a ^7 ? i took it as a transposition
oh that's probably right. my transposes look like little t's
Not even sure what a transposition is. Is that the right answer then?
it's like flipping a matrix on the diagonal axis.
AB
CD
turns into
AC
BD
so idk if it makes sense in this equation unless 4-2 gets converted to a matrix
Now you made me doubt... if you look at the tallies carefully, you will see they are actually 2 sticks too. That answer might be wrong.
en.wikipedia.org
on a 1x1 matrix it doesn't change anything though so if these are matrix and it's not a ^7 then it's right, i don't know how op intended it to be though.
Could you show me that equation written on paper?
or both might be right ;) i'll keep working on it though
4 left
(4-1)(4+2)^1=18
not sure if by removing the upper part of 7 u get a 1
Then you got it almost right! The stick that changes is the 7, turning into a T!!!! :D
3x2 isn't 18 though
this looks right to me
i think you have to read it [4 -1][4;-2]'=18
i was far from it though
up-to-date
The more I look at "+ == -++" the more I think it is wrong. In all the other equations they have never used the double "=="...
i've only seen == in computer science, which is a comparison.
in computer science, the statement + == -++ doesn't make sense in any language.
i still think the transpose 1 is still probably wrong and is the real answer
But you cannot turn the "7" into a "1" moving only one stick. But you can turn it into a "T"
it's like a tilted 1. like a /.
maybe its supposed to stay a 7 then. i just dont think it makes sense as is.
it's wrong as i said it (2 1x1 matrix) but if you see it as a 1x2 matrix and a 1x2 transposed matrix then i think it's right
Gentlemen, I am sorry, but I have to go to sleep. I will not be making more updated with the solutions.
Have a good night, and hope you get the rest :)
It has been a lot of fun! Take care
(x^2-8x)/x = x-8 if you do the limit with x->8 you get 0, not 1 so the lim one is wrong
he currently has it as 3-2 = 18
[4 -2] transposed is 2 so your original one would be (4 + 1)(2) = 10, which is right, if it is a transposition sign. the equation above it has the same sign but it was used as a 7 so idk which we are supposed to go by.
limit az x tends to 8 of x^2 - 9x over x=-1
Seeing this I couldn't help but think of this show
Now this sounds correct!!!
(Last update! really!)
will we at least get the answers ?
it's the wrong match but nice find still