Do we have any geniuses here? Possible contenders should be able to solve this high-level university problem with ease:
>If a coin is tossed 12 times, the outcome can be recorded as a 12-character sequence of H’s and T’s according to the results of the successive tosses. In how many ways can there be 4 H’s and 8 T’s?
Do we have any geniuses here? Possible contenders should be able to solve this high-level university problem with ease:
William Ortiz
Ian Thomas
120
Hudson Thomas
nope. Good try though user.
Gabriel Moore
>f of z equals summation from x to infinity (n=0,1,2,3,4,5...infinity) b sub n multiplied by z-a squared to the nth
suck my dick faggot
Charles Torres
Correct. 12^2 is 144. There would be 24 outcomes of 1H or 1T, twelve of each. So 144-24=120.
Kayden Ross
It's independent though. Each new attempt doesn't change the probability of the next throw you brainlet, try again.
Lincoln Foster
>It's independent though
>waahhh
Austin Green
It's just 12C4, which is 495. (Choosing heads.) You can confirm it because 12C8 (choosing tails) is also 495.
Blake Johnson
Also this is not a high-level university problem, you retards should have all learned this in high school.
Nathan Morales
So we have a set of 12 possibilities, and from it we need to choose 4 heads OR choose 8 tails.
Binomial Coefficient it is then.
Either 12 choose 4, OR 12 choose 8.
Either or, it's 495.