You should be able to solve this Yea Forums

You should be able to solve this Yea Forums

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62? 2 people get in (and 2 people get out when necessary) every minute for 30 minutes, plus the 2 people that get in at minute 0 when the ride opened?

42?

So what it's (10x2)30?

wouldn't it be 60 then, from 10:00 to 10:29, because it shuts down at 10:30, so that minute doesn't count

Ends up too straightforward, if that's the case then it's 58.

ok here is a hint

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40 people, because if the ride shut down at 10:30, it must mean that's the time the last person got off, and therefore no one gets on the ride for the last ten minutes.

no because it's two passengers per car. it's 60, you guys are overthinking it. it's two people per minute for thirty minutes 2x30

>I haf twelve matchsteek

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It's going to be a bullshit answer isn't it?

this thing is barely moving if one car goes through the platform every minute. this is bullshit

so it's going to take 9 minutes per ride, right? we have no way of knowing how many passengers they let onto the ride leading up to the time of closure.

Let me get the fixed for you op

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No, wait, 42 people, forgot two people get in the cabin at 10.

time to move on, this guy got it right.

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His arse

You would still have 20 people stuck on the ride when it shuts down.

2 people get on at minute zero.
2 people get on per minute for 10 minutes
2 people get on and off per minute for 10 minutes
2 people get off per minute for 10 minutes

His ass

The heart of a loved one.

Yeah that's gotta be his butt I reckon

Underneath his chair.

His anus

>10 x 2 seats
>max # of people
20

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This.

its 6

correct

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isn't this just 1/53*1/52*1/51*1/50*1/49?

wait no, it's 4/53*3/52*2/51*1/50*1/49

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50%, you either do or you don't. :^()

m.youtube.com/watch?v=wlOdUATGuQY

no lol
here's one for you

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1/5. Every card that isn't an ace or a joker is irrelevant, all that matters is whether - of the five relevant cards - the last one you happen to flip is a joker or an ace.

Isn't this, like, one of the classic problems that requires a computer algorythm to solve?

ding ding ding correct

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6th day, it will start at 2m, and receive enough water for 2.6m

fuck this was hard but I think I got it

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Unless I overlooked something I think this was pretty easy

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the queens in the top left corner and bottom right corner conflict. Try again

>

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Is it really correct to call that guy lazy? It, ironically, took a lot of effort to set all that up, yeah?

text me.
Now fuck off.

fucking retard

youtube.com/watch?v=FWKcFjNDDRI

Ah, so they do. Think it should be fine if I flip their rows.

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nvmd

now the far right queen conflicts diagonally north-west

You're pretty stupid user.

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correct
incorrect

here is the ultimate challenge

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...

But I'm kind :)

at least post the real one, not the edited one.

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>guck me

This
>chocolat box with panties on

I did it but others beated me to it.

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Realize your Buddha nature and get off the wheel!

this one was easier since it gives you a starting point

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What the fuck, you could easily reach under you chair with a rod or something. Fuck Layton’s bullshit.

i dunno i found it harder because there is less freedom, but good job.

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Is this shit really for kids??

CBA to do the math but 1st is the 1, and at the end is 9 and 6, then in the middle you can just go nuts right? Or is there only one solution?

Pair up stuff where it's gonna come out as 3 or 4, and alternate those

Wait nvm I didn't look carefully enough

it is pegi 7 so yes

God, I'm stupid

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