Well, Yea Forums?

63 + 35, I meant

Ah, I've got it now.

If a line n is drawn through B, parallel to l and m, then the interior angle of triangle ABC above n is 35°, and the interior angle below n is 19°, since 54 - 35 = 19.

This means that angle BCE is also 19°, which also means angle BCE (19°) + angle BCA (63°) = 82°

Then x = 180 - 82 = 98°

The angle at the bottom of the cutoff page is not necessarily 35 degrees just because the top angle is 35 degrees. One way to solve the problem is to acknowledge that angle BAC is 63 therefore angle DAC is 35+63=98 degrees. Since lines l and m are parallel and line AC traverses those parallel lines angle DAC and x are congruent. Thus x is 98.
This is basic middle school geometry and you should feel ashamed for not getting it easily. Don't take that too seriously, I'm just extracting the pound of flesh due me

Attached: don't ask questions.jpg (500x369, 38K)

Attached: solved.jpg (1280x936, 102K)

I owe you no such thing, as I worked it out before you posted.

Attached: [Commie] 3-gatsu no Lion - 42 [BD 720p AAC] [DE87F97D] 00:14:11.017-0001.png (1280x720, 1.09M)

Attached: [Commie] 3-gatsu no Lion - 42 [BD 720p AAC] [DE87F97D] 00:15:24.924-0002.png (1280x720, 948K)

fug u right. Ok then attempt, so I can bully you for real.

draw a line perpendicular to m at point c then get the little angle to get 98 degrees

Attached: file.png (615x303, 9K)

idiot.
The shortest solution is this.

Attached: 1558158601023.png (1365x1077, 426K)

See it's one step shorter

I would love to solve this, professor, but I'm missing the C and X, which are the most important part.

The only correct answer.
You can't assume where X and C are if they're not clearly given in the example.

see

>professor hands you a paper with an incomplete assignment
>let me look up an assignment that somewhat resembles this one, and just assume that it's the same assignment
not how it works

You dumb nigger, they're literally two adjacent scenes from the same episode of 3-gatsu.

Where the fuck is x even? I cant find it.
Or is that the problem?

piece of cake :)

Attached: 1558158601023 (1).png (1311x988, 418K)

Nah the pic is just cropped.
Look at:

How is that relevant?
If I were a professor and I got my assignments from anime or other tv shows, but I fucked up the cropping and only got half the assignment, how is that the students fault for not realising where I got the assignment from and just looking it up on google?

I'm not great at math, but even I can tell that X has to be atleast bigger than 90 degrees.

It should be 98°.

>Angle BAD is 35°, so angle BCE must also be 35°, right?
Lolno, that's only true if the distance between B and each line is the same. Which is clearly not the case.

this?

Attached: 1558158601023 (1).png (1311x988, 419K)

90>82

That doesn't make sense though.
BA = BC, which means their lengths are equal.
That means that B is equidistant from both A and C.

What are you even implying? That I'm trying to get Yea Forums to do my homework? Or that I have a professor that handed me an incomplete assignment?

If B was right on either of those lines or even outside of those lines, you wouldn't have debated against B being equidistant from A and C just because BA = BC.

Nevermind, you're just trolling.
Surely you can't be this dumb, user.

Yes, hence why the triangle is at a slight angle. because the distance from B to D and from B to E aren't the same, so BAD =/= BCE

When did I debate against that?

easy mode

Attached: 1558158601023 (2).png (1535x1069, 437K)

So you're saying that just because B is in between those lines that means BA = BC. That's like saying 3 is between 0 and 10 so the difference between 0 and 3 is the same as between 10 and 3.

I'm sorry, I feel like a retard here, user. But, I still don't get it (although I have solved the problem earlier).

BA and BC are equal length segments. l and m are parallel lines.

That means that the distance from B to line l, is the same as the distance from B to line m, doesn't it?

He is right though? what are you even trying to say? that BA isn't equal to BC? because it clearly is, it's even written in the question.

>BA and BC are equal length segments. l and m are parallel lines.
correct
>That means that the distance from B to line l, is the same as the distance from B to line m, doesn't it?
not correct, see except instead of l and m he uses D and E

>except instead of l and m he uses D and E
D and E come from

Ah, I see now. A and B are not directly opposite eachother on the parallel lines. This is where I was confusing it.

Fucking derp.

Fortunately Hina has gotten the 19° and 63° angles in

But user, if I attempt this, and the thread 404s, how will I get the answer to you? D:

think of the deletion as a time limit for a test. how the fuck do i solve for u and w?

Attached: help.png (1200x932, 250K)

curious to anons that couldn't solve this, what is your job?

Attached: 1555677956717.jpg (1227x868, 68K)

I was taught to never interpret the image literally, and to use the values provided instead, as the images are usually representative.

You can never know, user. It would cause too much embarassment.

183/28?

Why would solve worthless problems like this in the first place? Oh yeah, because you attend public education, who will teach you geometry but not logic, because logic is bad for slaves.
t. engineer

user wtf are you doing?

poor spatial reasoning skills indicate low intelligence.

Attached: you should be able to solve this.png (900x720, 422K)

>At which point of this cuboid should you choose
Choose what? And why am I supposed to choose something at a specific point?

don't be a shitter just answer the damn question.

Im supposed to know this but I cheated on my tests

Attached: 1268054599059.gif (276x252, 585K)

the point shouldn't be on the corner or else it'll just crawl up the edges. you have to make it cross the face of the rectangle, like how a hypotenuse of a right triangle is longer than the sides.

Attached: 1558173557815.png (900x720, 404K)

If you are old enough to be on this board then there's no excuse to struggle with basic geometry like the one in OP.

Consider getting off this shithole and study if you did.

>Consider getting off this shithole and study if you did.

Don't forget, you're here forever.

98

I'm assuming this is one of those computationally hard, or unsolved questions in mathematics.

Because solving problems is fun?

It's B. What the fuck is this lol?

I apparently have a reading comprehension problem or maybe it’s just because I’ve been up for so long, but I never even thought about the possibility that it could crawl along anything other than the edges.

the answer is clearly AI YO

It's 180-(180-54)/2-(180-(180-54)-35)=98, you should be able to see why from my formula.

You can calculate the angles a and b from the original triangle, then side opposite a' from cosine theorem, then the angles a'', a''', then you can calculate c, from which you get z and w, cosine theorem again for v.
But it's faster to just calculate from a''', b the angles of the u,A triangle, and then you can get A directly from the a'',a''' side.
I leave the details of the calculation to the reader.

Whoops, got the order mixed up.

I've gotten to the same point you have. I suspect you might be able to apply some SOHCAHTOA, but apply the respective trig function to the right angle of 90 degrees, and then rearrange from there.

That's what I'm going to do next.

The last side of the triangle is √(16-9) + √(49-9) = √7 + √40. Let this be equal to x.
The degree of elevation of the upper triangle's longest side is arcsin(√40 / 7) + arcsin(3 / 4) - 90°. Let the two arcsin values be p and q respectively. We also notice that the sum of the two arcsin values and the angle formed between the topmost side and line A is 180°. Let y = A - 3, then y
= x cos (180° - p - q)
= - x cos (p + q)
= x (sin p sin q - cos p cos q)
= x[(√40 / 7)(3 / 4) - (3 / 7)(√7 / 4)]
= (√40 + √7)(3)(√40 - √7)/28
= 3(40 - 7)/28 = 99/28 = 3 + 15/28
Therefore A = y + 3 = 6 + 15/28

Quantum tunnel through the cuboid.

Don't quite think that's the way to do it bros

Whoops, forgot to attach image.

Attached: trianglemath.png (1200x932, 285K)

is the bug able to walk on the surface or just on the black lines?

>this thread is still alive
are mods sleeping or what

Oh wow, someone beat me to it.